dikethui deret aritmetika U5=27 dan U6=33 tentukan U1 dan U12

63+6 = 69-(U12)
57+6 = 63(U11)
51+6 = 57(U10)
45+6 = 51(U9)
39+6 = 45(U8)
33+6 = 39(U7)
27+6 =33(U6)
33 - 6 = 27(U5)
27 - 6 = 21(U4)
21 - 6 = 15(U3)
15 - 6 = 9-(U2)

69 & 9

Jadikan jawaban yang terbaik ya please :-)

U6 - U5 = 33 - 27
6b - 5b = 6
b = 6 ✔

➡Suku pertama (U1)

U6 = a + 5b
33 = a + 5(6)
33 = a + 30
33 - 30 = a
3 = a

U1 = a = 3 ✔

➡Suku ke 12

U12 = a + 11b
U12 = 3 + 11(6)
U12 = 3 + 66
U12 = 69 ✔