sebanyak 100 ml larutan H2SO4 0,25 nol Tentukan Phnya

Diketahui :
V larutan H2SO4 = 100 ml
Molaritas H2SO4 = 0,25 M
a = Valensi asam

Ditanya : pH asam ?

Jawab :

H2SO4 -----> 2H+ + SO4²-

a = 2

[H+] :
= a . M
= 2 . 0,25 M
= 5 × 10-¹ M

pH larutan :
= - log [H+]
= - log 5 × 10-¹
= - ( log 5 + log 10-¹)
= - log 5 - log 10-¹
= 1 - log 5
= 1 - 0,7 = 0,3