tentukan ph larutan dari NH4OH 0,001 M.Kb =2×10-5

#ph larutan
#basa lemah
#XI semester 2

OH- = akar Kb Mb
= akar 2.10-5 x 0,001
= akar 2.10-8
= 1,41.10-4 M

pOH = 4 - log 1,41
pH = 10 + log 1,41


@kimiaischemistry