Kuat arus primer 6A memiliki lilitan primer 20 lilitan dan 40 lilitan sekunder. Carilah kuat arus sekunder dan tegangan sekunder bila tegangan primernya 10

diket :
Np = 20
Ns = 40
Vp = 10 v
Ip = 6 A
dit : Vs & Is
jwb :
# Tegangan sekunder
Vs = ( Ns . Vp ) / Np
Vs = ( 40 . 10 ) / 20
Vs = 400 / 20
Vs = 20 volt
# Arus sekunder
Is = ( Ip . Vp ) / Vs
Is = ( 6 . 10 ) / 20
Is = 60 / 20
Is = 3 A

np/ns = vp/vs
20/40 = 10/vs
vs = 2 x 10
vs = 20 V

vp/vs = Is/Ip
10/20 = Is/6A
6A/2 = Is
Is = 3A