Diketahui Sin a°= -2/3 dan cos a°= -1/2√3, Carilah; Tan a, Sec a, Cot a, Cosec a
Matematika
Takashi11
Pertanyaan
Diketahui Sin a°= -2/3 dan cos a°= -1/2√3, Carilah; Tan a, Sec a, Cot a, Cosec a
1 Jawaban
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1. Jawaban salwabila74
sin a° = -2/√3
cos a° = -½√3
tan a° = sin/cos
tan a° = (-2/√3) / (-½√3)
tan a° = (-2÷1/√3) / (-½÷1/√3)
tan a° = ( -2×√3) / (-½×1/√3)
tan a° = (-2√3) / (-1/2√3)
tan a° = (-2/√3) × (2√3/-1)
tan a° = -4/-1
tan a° = 4
sec a° = 1/cos
sec a° = 1/-½√3
sec a° = 1 × -2√3
sec a° = -2√3
cot a° = 1/tan
cot a° = 1/4
cosec a° = 1/sin
cosec a° = 1/-2√3
semoga membantu. maaf kalo salah:')