Matematika

Pertanyaan

Diketahui Sin a°= -2/3 dan cos a°= -1/2√3, Carilah; Tan a, Sec a, Cot a, Cosec a

1 Jawaban

  • sin a° = -2/√3
    cos a° = -½√3

    tan a° = sin/cos
    tan a° = (-2/√3) / (-½√3)
    tan a° = (-2÷1/√3) / (-½÷1/√3)
    tan a° = ( -2×√3) / (-½×1/√3)
    tan a° = (-2√3) / (-1/2√3)
    tan a° = (-2/√3) × (2√3/-1)
    tan a° = -4/-1
    tan a° = 4



    sec a° = 1/cos
    sec a° = 1/-½√3
    sec a° = 1 × -2√3
    sec a° = -2√3


    cot a° = 1/tan
    cot a° = 1/4


    cosec a° = 1/sin
    cosec a° = 1/-2√3




    semoga membantu. maaf kalo salah:')

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