Matematika

Pertanyaan

Tentukan unsur unsur yang dinyatakan pada barisan aritmatika tersebut . a. a=8 b=5 U10 b. b=15 U21=295 a= c. U10=34 U17=62 a=

1 Jawaban

  • Un = a + (n-1)b
    U9 = 5 + (9-1)3
    U9 = 5 + 24
    U9 = 29

    Sn = n/2 (2a + (n-1)b)
    S10 = 10/2 (2(5) + (10-1)3)
    S10 = 5 (10 +27)
    S10 = 185

    b. b=17, U21 = 336
    a= ?
    S8= ?

    U21 = a + (21-1) 17
    336 = a + 360
    a = 336-360 = -24
    S8 = 8/2 (2(-24) + (8-1) 17)
    S8 = 4 (-48 + 153)
    S8 = 4 (105)
    S8 = 420

    c.a = 21 , b=-8, Un  = -99
    n = ?
    Sn = ?
    -99 = 21 + (n-1)-8
    -99 = 21 - 8n + 8
    -99 -21 -8 = -8n
    -8n = -128
    n = 16
    Sn = 16/2 (2(21) + (16-1)(-8))
    Sn = 8 (42 + (-120))
    Sn = 8 (-78)
    Sn = -624

    d. a = 2 , b=9 n =15
    Un = ?
    Sn = ?
    U15 = 2 + (15-1)9
    U15 = 2 + 126
    U15 = 128
    S15 = 15/2 (2(2) + (15-1) 9)
    S15 = 15/2 (4 +126)
    S15 = 15/2 (130)
    S15 = 975

    e.a = 4, Un = -22 , Sn = -99
    b=  ?
    Un = 4 + (n-1)b
    -22 = 4 + (n-1)b
    -26/n-1 = b
    Sn = n/2 (2(4) + (n-1)b)
    -99 = n/2 (8 + (n-1)(-26/n-1))
    -99 = n/2 (8 -26)
    -99 = n/2 (-18)
    -9n = -99
    n = 11

    -26/11-1 = b
    b = -26/10
    b = -2,6





    nah

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