TOLONG BANTU YAA...NILAI TINGGI NIH
Matematika
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Pertanyaan
TOLONG BANTU YAA...NILAI TINGGI NIH
2 Jawaban
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1. Jawaban delawahyu1
f(x) = (X^6 + 1³) / (X^3 - 2³) = (X³-1) -
2. Jawaban nazua7
F(×) =(×^6+1³) /(×^3-2³)=(׳-1)