persamaan garis melewati titik P (2,8) dan Q (4,6)

[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \frac{y - 8}{6 - 8} = \frac{x - 2}{4 - 2} \\ =(y - 8) \times 2 = (x - 2) \times - 2 \\ 2y - 16 = - 2x + 4 \\ 2y = - 2x + 20 \\ y = - x + 10 [/tex]