Tuliskan persamaan garis berikut a. (-1, -4) dan (2,6) B. (8, -5) dan (1,3)

a)
[tex] \frac{y-y1}{y2-y1} = \frac{x-x1}{x2-x1} \\ \frac{y-(-4)}{6-(-4)} = \frac{x-(-1)}{2-(-1)} \\ \frac{y+4}{10} = \frac{x+1}{3} \\ 3(y+4)= 10(x+1) \\ 3y+12 =10x+10 \\ 3y=10x+10-12 \\ 3y=10x-12[/tex]

b)
[tex] \frac{y-y1}{y2-y1}= \frac{x-x1}{x2-x1} \\ \frac{y-(-5)}{3-(-5)} = \frac{x-8}{1 -8} \\ \frac{y+5}{8}= \frac{x-8}{-7} \\ -7(y+5)= 8(x-8) \\ -7y-35=8x-64 \\ -7y=8x-64+35 \\ -7y=8x-29[/tex]