mohon bantuannya yahhhh

a. tetha 1 = 2.phi.[tex] \frac{t}{T} [/tex] = 2.phi[tex] \frac{t}{1/3} [/tex]=2.phi.(3t) = 6 phi.t
    tetha 2 = 2.phi.[tex] \frac{t}{T} [/tex] = 2.phi[tex] \frac{t}{1/4} [/tex]=2.phi.(4t) = 8 phi.t

b. fase 1 = [tex] \frac{t}{1/3} =3t[/tex]
    fase 2 = [tex] \frac{t}{1/4} =4t[/tex]

c. fase 1 = 3t = 3 (1/12) = 1/4
    fase 2 = 4t = 4 (1/12) = 1/3
   beda fase = 2.phi.[tex](\frac{1}{3}- \frac{1}{4} )[/tex] = 2.phi.[tex]( \frac{1}{12} )[/tex] = [tex] \frac{phi}{6} [/tex]