Nilai dari 5log 75 + 2log 1/64 + 5log 4 - 5log 12

5log 75= 5log(3×25) = 5log3 + 5log25 = 5log3 +2
2log(1/64) = 2log(2∧(-6)) = -6
5log12 = 5log(4×3) = 5log4 + 5log3
Penyelesaian dari 5log 75 + 2log 1/64 + 5log 4 - 5log 12
=5log3 + 2 - 6 + 5log 4 - 5log4 - 5log3
= -4

= 5log (3.5²) + 2log (2⁻⁶) + 5log 2² - 5log (3.2²)
= 5log 3 + 2(5log 5) + -6(2log 2) + 2(5log 2) - 5log 3 - 2(5log 2)
= 5log3 - 5log3 + 2(1) - 6(1) + 2(5log 2) - 2(5log 2)
= 2 - 6
= - 4

catatan :
alog a = 1