Melalui (1,-5) sejajar garis 4× + 2y=5

rumus cepat tampa gradien
4u-2y=4u-2y
4u-2y=4(1)-2(-5)
4u-2y=4+10
4u-2y=14

(1,-5) sejajar 4×+2y=5
2y= -4×+5
y = -4×/2 + 5/2
y = -2× + 5/2
m1 = m2 = -2× (1,-5)
y-y1 = m1 (x-x1)
y-(-5) = -2(x-1)
y+5 = -2x+2
y = -2x +2-5
y = -2x-3
y+2x+3=0