integral x^2 akar 2x ^ 3 + 3 dx

InteGral SuBstituSI

u = 2x³ + 3
du = 6x²  dx
x² dx  = 1/6 du

∫ (x²) √(2x³ + 3) dx = 
= ∫¹/₆ √u du
= ¹/₆ ∫u¹/² du
= ¹/₆.²/₃ . u³/² + c
= ¹/₉.u√u + c
= ¹/₉ (2x³ + 3) √(2x³ + 3) + c