tent nilai c dan d plisss jawab butuh banget soalnyaa

sudut 130° dengan sudut c° dan sudut 2d° dengan c° adalah sudut luar sepihak, maka:
[tex]{130}^{0} + {c}^{0} = {180}^{0} \\ {c}^{0} = {180}^{0} - {130}^{0} \\ {c}^{0} = {50}^{0} [/tex]
[tex] {c}^{0} + {2d}^{0} = {180}^{0} \\ {50}^{0} + {2d}^{0} = {180}^{0} \\ {2d}^{0} = {180}^{0} - {50}^{0} \\ {d}^{0} = \frac{ {130}^{0} }{2} \\ {d}^{0} = {65}^{0} [/tex]
jadi c = 50° dan d = 65°